mysql — ошибка синтаксиса PHP на MyISAM & gt; InnoDB: ожидание ‘}’

При выполнении скрипта Я нашел в Интернете что кто-то создал, чтобы преобразовать MyISAM в InnoDB, он выдает синтаксическую ошибку, которую я пытался выяснить и вставил случайным образом (совсем не так глубоко в PHP-программисте.) Кто-то любезно помог бы программисту на python?

[root@server~]# php cli-mysql-to-innodb.php
PHP Parse error:  syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting '}' in /root/cli-mysql-to-innodb.php on line 44

Линии 40-53:

 40 while ($row= $results->fetch_assoc()) {
41         $sql = "SHOW TABLE STATUS WHERE Name = '{$row['Tables_in_' . $db['database']]'";
42         $thisTable = $mysqli->query($sql)->fetch_assoc();
43
44          if ($thisTable['Engine']==='MyISAM') {
45                 $sql = "alter table " . $row['Tables_in_' . $db['database']]. " ENGINE = InnoDB;";
46                 echo "Changing {$row['Tables_in_' . $db['database']]} from {$thisTable['Engine']} to InnoDB.\n";
47                 $mysqli->query($sql);}
48         } else {
49                 echo $row['Tables_in_' . $db['database']] . ' is of the Engine Type ' . $thisTable['Engine'] . ".\n";
50                 echo "Not changing to InnoDB.\n\n";
51         }
52 }
53

Общий сценарий

<?php
/*
* Use this version if you are NOT a Pantheon customer.
*/
$db = array();

/*
* Change these to match your database connection information
*/
$db['host']     = "localhost";
$db['port']     = "3306";
$db['user']     = "";
$db['password'] = "";
$db['database'] = "";

/*
* DO NOT CHANGE ANYTHING BELOW THIS LINE
* Unless you know what you are doing. :)
*/
$db['connectString'] = $db['host'];

if (isset($db['port']) && (int)$db['port']==$db['port']) {
$db['connectString'] .= ":" . $db['port'];
}

$mysqli = @new mysqli($db['connectString'], $db['user'], $db['password'], $db['database']);

if ($mysqli->connect_errno) {
echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error ."\n";
die(1);
}

$results = $mysqli->query("show tables;");

if ($results===false or $mysqli->connect_errno) {
echo "MySQL error: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error ."\n";
die(2);
}

while ($row= $results->fetch_assoc()) {
$sql = "SHOW TABLE STATUS WHERE Name = '{$row['Tables_in_' . $db['database']]'";
$thisTable = $mysqli->query($sql)->fetch_assoc();

if ($thisTable['Engine']==='MyISAM') {
$sql = "alter table " . $row['Tables_in_' . $db['database']]. " ENGINE = InnoDB;";
echo "Changing {$row['Tables_in_' . $db['database']]} from {$thisTable['Engine']} to InnoDB.\n";
$mysqli->query($sql);
} else {
echo $row['Tables_in_' . $db['database']] . ' is of the Engine Type ' . $thisTable['Engine'] . ".\n";
echo "Not changing to InnoDB.\n\n";
}
}

die(0);

0

Решение

вы не закрыли скобку в этой строке 41,

$sql = "SHOW TABLE STATUS WHERE Name = '{$row['Tables_in_' . $db['database']]'";

попробуй вот так

 $sql = "SHOW TABLE STATUS WHERE Name = '{$row['Tables_in_' . $db['database']]}'";
1

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